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Source:https://github.com/SoraKumo001/next-streaming

seanhunter 1 daysReload

This is set out in the NLRA which is 29 US code 157 https://www.law.cornell.edu/uscode/text/29/157 I'm not a lawyer and it seems not straightforward.

seanhunter 1 daysReload

The DOJ antitrust division's mandate is to promote competition by enforcing antitrust law. They aren't really concerned with worker's rights except insofar as those rights are affected by anticompetitive behaviours such as non-competes etc[1], so I'm not sure the AWU are going to get very far here.

[1] https://www.justice.gov/atr/mission

seanhunter 1 daysReload

Well the proof I would use is let a = e and b = i(pi).

e^(i theta) = cos theta + i sin theta (Euler's identity) thus e^(i pi) = cos pi + i sin pi = -1 + i(0) = -1

We know that e and i pi are irrational (in fact i pi isn't even a real) and -1 is rational.

Therefore there exist two numbers a and b such that both a and b are irrational but a^b is rational.

In fact log of just about anything is irrational so e^(log x) works as well for just about all rational x, but Euler's identity is cool so I wanted to use that.

seanhunter 2 daysReload

No Taylor liked to communicate the series musically on various organs. IT got expensive and that’s why noone ever goes beyond the first two or three terms.

seanhunter 2 daysReload

That is referenced in both the paper and the video in fact. Apparently Diaconis presented a model which predicted about 51% preference for "Same side" and also did 2500 flips and said that about 250k flips would be needed to get 3 sigma of significance. So this paper decided to test it empirically and got to about exactly that number after 350k flips from a team of researchers.

seanhunter 2 daysReload

seanhunter 1 daysReload

Well the proof I would use is let a = e and b = i(pi).

e^(i theta) = cos theta + i sin theta (Euler's identity) thus e^(i pi) = cos pi + i sin pi = -1 + i(0) = -1

We know that e and i pi are irrational (in fact i pi isn't even a real) and -1 is rational.

Therefore there exist two numbers a and b such that both a and b are irrational but a^b is rational.

In fact log of just about anything is irrational so e^(log x) works as well for just about all rational x, but Euler's identity is cool so I wanted to use that.

seanhunter 1 daysReload

This is set out in the NLRA which is 29 US code 157 https://www.law.cornell.edu/uscode/text/29/157 I'm not a lawyer and it seems not straightforward.

seanhunter 2 daysReload

No Taylor liked to communicate the series musically on various organs. IT got expensive and that’s why noone ever goes beyond the first two or three terms.